Answer by user3133925 for Is O(log n) always faster than O(n)
For the input of size n, an algorithm of O(n) will perform steps proportional to n, while another algorithm of O(log(n)) will perform steps roughly log(n).Clearly log(n) is smaller than n hence...
View ArticleAnswer by Alex D for Is O(log n) always faster than O(n)
No, it will not always be faster. BUT, as the problem size grows larger and larger, eventually you will always reach a point where the O(log n) algorithm is faster than the O(n) one.In real-world...
View ArticleAnswer by a3nm for Is O(log n) always faster than O(n)
No. If one algorithm runs in N/100 and the other one in (log N)*100, then the second one will be slower for smaller input sizes. Asymptotic complexities are about the behavior of the running time as...
View ArticleIs O(log n) always faster than O(n)
If there are 2 algorthims that calculate the same result with different complexities, will O(log n) always be faster? If so please explain. BTW this is not an assignment question.
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